Question:medium

In terms of Bohr radius \(a_0\), the radius of \(2^{nd}\) Bohr orbit of Hydrogen is:

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Radius of Bohr orbit: \[ r_n=n^2a_0 \] Thus: \[ r_1=a_0,\qquad r_2=4a_0,\qquad r_3=9a_0 \]
Updated On: May 17, 2026
  • \(4a_0\)
  • \(8a_0\)
  • \(\sqrt{2}a_0\)
  • \(2a_0\)
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The Correct Option is A

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