Step 1: Use E = k l:
The cell emf $E$ is fixed. At balance, $E=k\,l$.
Step 2: Track k:
A longer wire has a larger resistance, so the current from the driving source falls, and the potential drop per unit length ($k=IR/L$) falls.
Step 3: Conclude:
For fixed $E$, a smaller $k$ needs a larger $l$, so the balancing length increases. Option B.
Final Answer:
A longer wire lowers the potential gradient, so the null point moves farther.
\[ \boxed{\text{(B) }\text{increase}} \]