In potassium trioxalatoferrate(III), what are the primary and secondary valency of central atom respectively?

Question

5.33 gram of $CrCl_3 \cdot 6H_2O$ (1:3 electrolyte) is passed through cation exchanger. The resulting solution is then treated with an excess of $AgNO_3$, leading to formation of 8.61 gran of precipitate. Calculate :
$\frac{\text{number of moles of complex reacted}}{\text{number of moles of AgCl precipitated}} \times 100$

Answer 1

Step 1: Understanding the Concept:
According to Werner's Theory, Primary Valency corresponds to the Oxidation State, and Secondary Valency corresponds to the Coordination Number.
Step 2: Formula Application:
The formula is $K_3[Fe(C_2O_4)_3]$. Oxidation state of Fe: $3(+1) + x + 3(-2) = 0 \implies x = +3$ (Primary Valency).
Step 3: Explanation:
Oxalate ($C_2O_4^{2-}$) is a bidentate ligand, meaning it forms two bonds per ligand. Coordination Number = $3 \text{ ligands} \times 2 \text{ bonds/ligand} = 6$ (Secondary Valency).
Step 4: Final Answer:
Primary valency is 3 and secondary valency is 6.

Column-I (Complex compound)	Column-II ($\Delta_0$ (CFSE) $\text{cm}^{-1}$)
(i) $[Cr(CN)_6]^{3-}$	(P) 17000
(ii) $[Cr(H_2O)_6]^{3+}$	(Q) 15000
(iii) $[Cr(en)_3]^{3+}$	(R) 12000
(iv) $[CrF_6]^{3-}$	(S) 20000

In potassium trioxalatoferrate(III), what are the primary and secondary valency of central atom respectively?

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The Correct Option is A

Solution and Explanation

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