Question

In photoelectric effect experiment, if the frequency of incident radiation (\(v\)) is increased, keeping all other factors constant, the stopping potential, ( \(v > v_0\)) (\(v_0\) = threshold frequency)

• A. decreases
• B. remains the same
• C. increases
• D. becomes zero

Hint:

eV0 = h nu - phi, so V0 increases with frequency.

Answer 1

The Correct Option is C

Step 1: Formula
$V_0 = \dfrac{h}{e}(\nu - \nu_0)$.

Step 2: Trend
Larger $\nu$ gives larger $V_0$.

Step 3: Answer
Option (C).

Final Answer:
Option (C). \[ \boxed{\text{Increases}} \]