Step 1: Check dimensions of the options:
The ratio of two accelerations is dimensionless. $V^2/(r^2\alpha)$: $\dfrac{\text{m}^2\text{s}^{-2}}{\text{m}^2\text{s}^{-2}}$ works, since $\alpha$ has unit $\text{s}^{-2}$.
Step 2: Check the others:
A: $\dfrac{\alpha r}{V}$ has unit $\dfrac{\text{s}^{-2}\text{m}}{\text{m s}^{-1}}=\text{s}^{-1}$, not dimensionless. D: $\dfrac{r\alpha^2}{V^2}$ has unit $\text{s}^{-2}\text{m}^{-1}$, not dimensionless. C is the inverse of B, so it is correct only if the ratio is tangential over radial.
Step 3: Pick:
Option B, which equals $\dfrac{V^2/r}{\alpha r}$.
Final Answer:
Radial acceleration is V^2/r, tangential is alpha r, so the ratio is V^2/(r^2 alpha).
\[ \boxed{\text{(B) }\dfrac{V^2}{r^2\alpha}} \]