Given:
Charge on oil drop, Q = −1.282 × 10−18 C
Charge of one electron, e = 1.602 × 10−19 C
Step 1: Use relation between charge and number of electrons
Q = n × e
n = Q / e
Step 2: Calculate number of electrons
n = (1.282 × 10−18) / (1.602 × 10−19)
n = 8
Final Answer:
Number of electrons present on the oil drop = 8
Considering Bohr’s atomic model for hydrogen atom :
(A) the energy of H atom in ground state is same as energy of He+ ion in its first excited state.
(B) the energy of H atom in ground state is same as that for Li++ ion in its second excited state.
(C) the energy of H atom in its ground state is same as that of He+ ion for its ground state.
(D) the energy of He+ ion in its first excited state is same as that for Li++ ion in its ground state.