Question:medium

In metre bridge experiment, the resistance in the left gap is 15 \(\Omega\) and in the right gap is 45 \(\Omega\). The bridge is balanced. The distance of the null point from the centre of the wire is

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Balance condition: R_left / R_right = l / (100 - l); then subtract 50 cm.
Updated On: Oct 1, 2026
  • \(80\) cm
  • \(60\) cm
  • \(40\) cm
  • \(25\) cm
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Wire ratio
Lengths are in the ratio of resistances: $l : (100 - l) = 15 : 45 = 1 : 3$.

Step 2: Position
So $l = 25$ cm from the left end.

Step 3: From centre
$50 - 25 = 25$ cm. Option (D).

Final Answer:
Option (D). \[ \boxed{25 \text{ cm}} \]
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