Question:medium

In long form of periodic table an element 'E' has atomic number 78. The period and group number of the element are x and y respectively. (x+y) is equal to

Show Hint

To quickly find the period of an element with atomic number Z, locate it between the atomic numbers of the noble gases (2, 10, 18, 36, 54, 86, 118). The period number corresponds to the row of the next noble gas. For the group, identify the block (s, p, d) and apply the corresponding rule.

Updated On: Mar 30, 2026

18
15
17
16

Show Solution

The Correct Option is D

Solution and Explanation

Was this answer helpful?

0

Top Questions on Inorganic chemistry

Questions Asked in TS EAMCET exam

If $\omega \neq 1$ is a cube root of unity, then one root among the $7^{th}$ roots of $(1+\omega)$ is

TS EAMCET - 2025
Complex numbers

If $A = \begin{pmatrix} 1 & 2 & 3 \\ 2 & 1 & 1 \\ 1 & 3 & 1 \end{pmatrix}$ and $B = \begin{pmatrix} 2 & 3 & 4 \\ 3 & 2 & 2 \\ 2 & 4 & 2 \end{pmatrix}$, then $\sqrt{|\text{Adj}(AB)|} =$

TS EAMCET - 2025
Matrices and Determinants

If \( p_1, p_2, p_3 \) are the altitudes and \( a=4, b=5, c=6 \) are the sides of a triangle ABC, then \( \frac{1}{p_1^2} + \frac{1}{p_2^2} + \frac{1}{p_3^2} = \)

TS EAMCET - 2025
Geometry

If \(\alpha, \beta, \gamma, \delta, \epsilon\) are the roots of the equation \(x^5 + x^4 - 13x^3 - 13x^2 + 36x + 36 = 0\) and \(\alpha<\beta<\gamma<\delta<\epsilon\) then \( \frac{\epsilon}{\alpha} + \frac{\delta}{\beta} + \frac{1}{\gamma} = \)

TS EAMCET - 2025
Algebra