Question

In hydrogen atom, transition from the state \( n = 6 \) to \( n = 1 \) results in ultraviolet radiation. Infrared radiation will be obtained in the transition

• A. \( n = 3 \text{ to } n = 1 \)
• B. \( n = 4 \text{ to } n = 2 \)
• C. \( n = 6 \text{ to } n = 2 \)
• D. \( n = 5 \text{ to } n = 3 \)

Hint:

Lyman $\to$ UV, Balmer $\to$ Visible, Others $\to$ Infrared.

Answer 1

The Correct Option is D

Step 1: Understanding the Question:
The spectral series of hydrogen are classified by their final energy level \( n_{\text{final}} \).
Step 3: Detailed Explanation:
- Lyman Series (\( n_{\text{final}} = 1 \)): Ultraviolet (UV) region.
- Balmer Series (\( n_{\text{final}} = 2 \)): Visible region.
- Paschen Series (\( n_{\text{final}} = 3 \)): Infrared (IR) region.
Analyzing the options:
(A) Ends at \( n=1 \) (Lyman, UV).
(B) and (C) End at \( n=2 \) (Balmer, Visible).
(D) Ends at \( n=3 \). This is the Paschen series, which is in the Infrared region.
Step 4: Final Answer:
Transition from \( n=5 \) to \( n=3 \) gives infrared radiation.