Step 1: Read the constraint.
The word MULTIPLE has $8$ letters and we keep every vowel locked in its original spot.
Step 2: Identify the vowels.
The vowels are $U, I, E$; they stay fixed, so they contribute nothing to the count.
Step 3: Identify the consonants.
The remaining positions are filled by the consonants $M, L, T, P, L$, which is $5$ letters.
Step 4: Note the repetition.
Among these, the letter $L$ appears twice, so arrangements are reduced by a factor of $2!$.
Step 5: Count the consonant arrangements.
Number of ways $=\dfrac{5!}{2!}=\dfrac{120}{2}=60$.
Step 6: Conclude.
Since the vowels are fixed, the total is just $60$, which is option (1).
\[ \boxed{60} \]