Question

In case of stationary wave pattern, which of the following statement is CORRECT ?

• A. The distance between consecutive antinodes is equal to the wavelength.
• B. In a pipe open at both ends when an air column is vibrated, only even harmonics are present.
• C. When an air column is vibrated in a pipe closed at one end, all harmonics are present.
• D. In the case of a stretched string, when vibrated frequency of the first overtone is same as the second harmonic.

Hint:

For a string fixed at both ends, the first overtone is the second harmonic.

Answer 1

The Correct Option is D

Step 1: Recall the facts
Antinode spacing $\lambda/2$; open pipe all harmonics; closed pipe odd harmonics; string overtones $=$ harmonics shifted by one.

Step 2: Match
Only (D) agrees with these facts, option (D).

Final Answer:
Option (D) is the correct statement. \[ \boxed{\text{(D)}} \]