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In Carius method, $0.40\,g$ of an organic compound gave $0.188\,g$ of $AgBr$. The percentage of bromine in the compound is (Atomic mass of Ag = 108 g mol$^{-1}$ and Br = 80 g mol$^{-1}$)
In Carius method, $0.40\,g$ of an organic compound gave $0.188\,g$ of $AgBr$. The percentage of bromine in the compound is (Atomic mass of Ag = 108 g mol$^{-1}$ and Br = 80 g mol$^{-1}$)
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Use ratio of molar masses to extract element mass from compound.
Updated On: Apr 24, 2026
- 30%
- 25%
- 35%
- 24%
- 20%
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The Correct Option is
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