Step 1: Use angular momentum quantisation
Bohr gave $mVr=\frac{nh}{2\pi}$, so $Vr=\frac{nh}{2\pi m}$.
Since $h$, $m$ and $\pi$ are constants, $Vr$ is directly proportional to $n$.
Step 2: Pick the reciprocal
If $Vr\propto n$ then $\frac{1}{Vr}\propto\frac{1}{n}$, which is the inverse dependence the question asks for.
This matches option (A).
Step 3: Check the rest quickly
Using $r\propto n^2$ and $V\propto 1/n$: $V^2r$ stays constant, $Vr^2\propto n^3$, and $Vr\propto n$.
None of these falls as $n$ rises, so (B), (C) and (D) are out.
Final Answer:
Since $Vr\propto n$, the quantity $\frac{1}{Vr}$ falls as $1/n$. Option (A).
\[ \boxed{\text{(A)}} \]