Question:medium

In an $S_N1$ reaction on chiral centres, there is :

Updated On: May 29, 2026
  • 100% retention
  • 100% inversion
  • 100% racemization
  • inversion more than retention leading to partial recemization
Show Solution

The Correct Option is D

Solution and Explanation

The question pertains to S_N1 reactions involving chiral centers and asks about the stereochemical outcome. Let's analyze the process step-by-step:

  1. Understanding S_N1 Reactions:
    • S_N1 stands for Unimolecular Nucleophilic Substitution reaction.
    • This reaction occurs in two steps:
      • The leaving group departs, forming a carbocation intermediate.
      • The nucleophile attacks the carbocation, resulting in the formation of the product.
    • The carbocation, being planar, allows the nucleophile to attack from either side.
  2. Stereochemical Implications:
    • Due to the planar structure of the carbocation, nucleophilic attack can occur from both the front and back of the plane.
    • This results in the creation of two stereoisomers: one with retention of configuration and one with inversion of configuration.
  3. Outcome and Explanation:
    • Typically, in S_N1 reactions, while both retention and inversion occur, inversion is often more prevalent.
    • This is because the leaving group may hinder the nucleophile's approach from the front side, leading to a predominant backside attack that causes inversion.
    • Consequently, the product is partially racemized, with a slight predominance of the inverted configuration.
  4. Conclusion:
    • The correct answer is: "inversion more than retention leading to partial racemization".
    • Other options like "100% retention", "100% inversion", or "100% racemization" are incorrect due to the experimental outcomes typical of S_N1 reactions.

Thus, the given option that accurately describes the result of an S_N1 reaction on chiral centers is indeed "inversion more than retention leading to partial racemization".

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