Question

In an oscillating LC circuit, \(L = 1.6\,mH\), \(C = 4\,\mu F\). If the maximum charge is \(4 \times 10^{-6}\,C\), then the maximum current is:

• A. 75 mA
• B. 12.5 mA
• C. 125 mA
• D. 50 mA

Hint:

In LC circuits: \(I_{max} = Q_{max}\omega\) and \(\omega = 1/\sqrt{LC}\).

Answer 1

The Correct Option is D

Step 1: LC oscillation peak current.
I_max = Q_max ω, with ω = 1/√(LC).

Step 2: Component values.
L = 1.6×10⁻³ H, C = 4×10⁻⁶ F.

Step 3: Computing LC product.
LC = 6.4×10⁻⁹ → √(LC) = 8×10⁻⁵ → ω = 1.25×10⁴ rad/s.

Step 4: Current calculation.
I_max = (4×10⁻⁶)(1.25×10⁴) = 5×10⁻² A.

Step 5: Conclusion.
The maximum current is 50 mA.