Question:medium

In an LCR circuit, the current and emf differ in phase by $\Phi$. The value of $\Phi$ is:

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XL = ωL, XC = 1/(ωC). If XL greater than XC, circuit is inductive and voltage leads current.
Updated On: Feb 11, 2026
  • $\Phi = \tan^{-1}\left[\frac{(X_L - X_C)}{R}\right]$
  • $\Phi = \tan^{-1}\left[\frac{(X_L + X_C)}{R}\right]$
  • $\Phi = \tan^{-1}\left[\frac{R}{(X_L - X_C)}\right]$
  • $\Phi = \tan^{-1}\left[\frac{R}{(X_L + X_C)}\right]$
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The Correct Option is A

Solution and Explanation

The total impedance for a series LCR circuit is determined by
\[Z = \sqrt{R^2 + (X_L - X_C)^2},\]
while the phase angle \( \Phi \) (the angle between voltage and current) is calculated as
\[\tan \Phi = \frac{X_L - X_C}{R}.\]

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