Question:medium

In an ionic solid anions are arranged in hcp array and cations occupy $\frac{2}{3}$ of octahedral voids. What is the formula of ionic compound? [consider A = cation; B = anion]}

Show Hint

Number of Octahedral Voids = $N$; Number of Tetrahedral Voids = $2N$.
Updated On: May 12, 2026
  • AB
  • $A_2B_3$
  • $A_3B_2$
  • $AB_3$
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0