Question

In an ideal transformer, the turns ratio is \(N_p/N_s\) =1/2 .The ratio \(V_S:V_P\)  is equal to (the symbols carry their usual meaning):

• A. 1:2
• B. 2:1
• C. 1:1
• D. 1:4

Answer 1

The Correct Option is B

The turns ratio in an ideal transformer is defined by the equation: \( \frac{N_p}{N_s} = \frac{V_p}{V_s} \). Here:

• \(N_p\) denotes the primary coil turns.
• \(N_s\) denotes the secondary coil turns.
• \(V_p\) is the primary coil voltage.
• \(V_s\) is the secondary coil voltage.

Given a turns ratio of \( \frac{N_p}{N_s} = \frac{1}{2} \), the transformer equation yields:

\(\frac{V_p}{V_s} = \frac{1}{2}\)

Consequently:

\(V_s = 2 \times V_p\)

Therefore, the voltage ratio \( V_S:V_P \) is \(2:1\).

The correct voltage ratio is 2:1.