Question:medium

In an experiment with Vernier calipers of least count 0.1 mm, when two jaws are joined together the zero of Vernier scale lies right to the zero of the main scale and 6th division of Vernier scale coincides with the main scale division. While measuring the diameter of a spherical bob, the zero of Vernier scale lies in between 3.2 cm and 3.3 cm marks, and 4th division of Vernier scale coincides with the main scale division. The diameter of bob is measured as

Show Hint

Always remember: "Actual = Observed - (Zero Error)". If zero is to the right, error is positive (subtract). If zero is to the left, error is negative (effectively add).
Updated On: Apr 22, 2026
Show Solution

Solution and Explanation

Step 1: Understanding the Concept:
Measuring with Vernier calipers involves determining the main scale reading (MSR), the Vernier scale reading (VSR), and accounting for any zero error. Zero error occurs when the zeros of the main and Vernier scales do not align when the jaws are closed.
Step 2: Key Formula or Approach:
1. Zero Error ($e$) = $+ (n \times LC)$ if the Vernier zero is to the right (positive error).
2. Total Reading = $(MSR + VSR \times LC) - (\text{Zero Error})$.
Step 3: Detailed Explanation:
1. Calculate Zero Error: Since the Vernier zero is to the right, it is a positive zero error. \[ e = +(6 \times 0.1 \, \text{mm}) = +0.6 \, \text{mm} = +0.06 \, \text{cm} \]
2. Identify Observed Reading: - Main Scale Reading ($MSR$) = 3.2 cm (since the zero lies between 3.2 and 3.3). - Vernier Scale Reading ($VSR$) = 4th division. - Observed Value = $3.2 + (4 \times 0.01 \, \text{cm}) = 3.24 \, \text{cm}$.
3. Calculate Corrected Diameter: \[ \text{Diameter} = \text{Observed Value} - \text{Zero Error} \] \[ \text{Diameter} = 3.24 \, \text{cm} - 0.06 \, \text{cm} = 3.18 \, \text{cm} \]
Step 4: Final Answer
The diameter of the bob is 3.18 cm.
Was this answer helpful?
0