In an experiment with a closed organ pipe, it is filled with water by $\left(\frac{1}{5}\right)^{th}$ of its volume. The frequency of the fundamental note will change by

Question

A pipe open at both ends has a fundamental frequency $f$ in air. The pipe is now dipped vertically in water drum to half of its length. The fundamental frequency of the air column is now equal to:

Answer 1

Step 1: Ratio of frequencies
$\dfrac{f'}{f}=\dfrac{L}{L'}=\dfrac{L}{0.8L}=1.25$.

Step 2: Percentage form
$\dfrac{\Delta f}{f}=1.25-1=0.25$.

Step 3: Result
The change is $+25\%$, option (A).

Final Answer:
The fundamental frequency rises by 25 percent. \[ \boxed{\text{(A) }25\%} \]

In an experiment with a closed organ pipe, it is filled with water by \(\left(\frac{1}{5}\right)^{th}\) of its volume. The frequency of the fundamental note will change by

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The Correct Option is A

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