Question:medium
In an 8-bit microcontroller, if the program counter is 16-bit wide, then the maximum addressable memory space is:
In an 8-bit microcontroller, if the program counter is 16-bit wide, then the maximum addressable memory space is:
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Remember these standard binary exponential values:
- \(2^{10} = 1\text{ k}\) (Kilo)
- \(2^{20} = 1\text{ M}\) (Mega)
Therefore, a 16-bit address line gives \(2^{16} = 2^6 \times 2^{10} = 64\text{ kB}\) of addressable space.
- \(2^{10} = 1\text{ k}\) (Kilo)
- \(2^{20} = 1\text{ M}\) (Mega)
Therefore, a 16-bit address line gives \(2^{16} = 2^6 \times 2^{10} = 64\text{ kB}\) of addressable space.
Updated On: Jun 23, 2026
- \(64\text{ kB}\)
- \(128\text{ bytes}\)
- \(1\text{ MB}\)
- \(256\text{ kB}\)
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The Correct Option is A
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