Question

In a triangle ABC, If, AB = 6, BC = 8 and AC = 10. Further, if a perpendicular which is dropped from B, meets the side AC at D. A circle of radius BD (with center (b) is drawn. If the circle cuts AB and BC at P and Q respectively, the AP:QC will be equal to which of the following?

• A. 1:4
• B. 4:1
• C. 5:8
• D. 1:3
• E. 3:8

Hint:

In a right triangle, the altitude to the hypotenuse can be found using the area formula: $h = \frac{ab}{c}$.

Answer 1

The Correct Option is B