Question:medium

In a single slit diffraction experiment, slit of width 'a' and incident light of wavelength \( 5600\,\text{\AA} \), the first minimum is observed at angle \( 30^\circ \). The first secondary maximum is observed at angle \( (\sin 30^\circ = 0.5) \)

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- First minimum gives slit width - Secondary maxima $\approx (m+\tfrac{1}{2})\lambda$
Updated On: May 4, 2026
  • \( \sin^{-1} \left( \frac{1}{\sqrt{2}} \right) \)
  • \( \sin^{-1} \left( \frac{1}{2} \right) \)
  • \( \sin^{-1} \left( \frac{\sqrt{3}}{2} \right) \)
  • \( \sin^{-1} \left( \frac{3}{4} \right) \)
Show Solution

The Correct Option is D

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