Balanced reaction: A + B2 -> AB2 Stoichiometric ratio: \[ n(\text{A}) : n(\text{B}_2) = 1 : 1 \] So, compare the amounts of A and B₂ directly.
Required: 300 A needs 300 B₂ (1:1), but only 200 B₂ are present. Therefore, B₂ is limiting and A is in excess.
Required: 2 mol A needs 2 mol B₂. Present: 3 mol B₂. Therefore, A is limiting and B₂ is in excess.
Required: 100 A needs 100 B₂. Present: 100 A and 100 B₂. Neither is in excess; no limiting reagent, both are completely consumed.
Required: 5 mol A needs 5 mol B₂, but only 2.5 mol B₂ are present. Therefore, B₂ is limiting and A is in excess.
Required: 2.5 mol A needs 2.5 mol B₂. Present: 5 mol B₂. Therefore, A is limiting and B₂ is in excess.
| Case | Given Amounts | Limiting Reagent |
|---|---|---|
| (i) | 300 atoms A, 200 molecules B₂ | B₂ |
| (ii) | 2 mol A, 3 mol B₂ | A |
| (iii) | 100 atoms A, 100 molecules B₂ | None (both just sufficient) |
| (iv) | 5 mol A, 2.5 mol B₂ | B₂ |
| (v) | 2.5 mol A, 5 mol B₂ | A |
Calculate the number of moles present in 9.10 × 1016 kg of water.