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In a population, the frequency of a recessive allele (\(q\)) is \(0.4\). Calculate the frequency of homozygous dominant individuals?

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Hardy--Weinberg equilibrium: \[ \boxed{ p+q=1 } \] and \[ \boxed{ p^2+2pq+q^2=1, } \] where \[ \boxed{ p^2=\text{Homozygous dominant},\; 2pq=\text{Heterozygous},\; q^2=\text{Homozygous recessive}. } \]

Updated On: Jul 14, 2026

\(0.16\)
\(0.36\)
\(0.48\)
\(0.64\)

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The Correct Option is B

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In a population, the frequency of a recessive allele (\(q\)) is \(0.4\). Calculate the frequency of homozygous dominant individuals?

Show Hint

The Correct Option is B

Solution and Explanation

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