Question

In a parallel plate capacitor, if \(10^{12}\) electrons pass from one plate to another, a potential difference of \(10\,\text{V}\) is developed across the plates. The capacitance of the capacitor is:

• A. \(0.16\times 10^{-8}\,\text{F}\)
• B. \(1.6\times 10^{-8}\,\text{F}\)
• C. \(16\times 10^{-8}\,\text{F}\)
• D. \(0.8\times 10^{-8}\,\text{F}\)

Hint:

For capacitor problems involving transferred electrons, first calculate charge using \[ Q=ne \] and then use \[ C=\frac{Q}{V}. \]

Answer 1

The Correct Option is B

Step 1: Find the charge transferred.
\[ Q = ne = 10^{12}\times1.6\times10^{-19} = 1.6\times10^{-7}\,\text{C} \]

Step 2: Apply \( C = Q/V \).
\[ C = \frac{1.6\times10^{-7}}{10} = 1.6\times10^{-8}\,\text{F} \] \[ \boxed{1.6\times10^{-8}\,\text{F}} \]