Question

In a pack of 6 cards, two cards are marked with \(5\), two cards are marked with \(6\), one card is marked with \(7\) and another card is marked with \(8\). In another pack of 6 cards, one card is marked with \(5\), two cards are marked with \(6\), two cards are marked with \(7\) and one card is marked with \(8\). If one card from each pack is drawn at random, the probability that the sum of the numbers on the cards is \(12\) or \(13\) is

• A. \(\frac{3}{5}\)
• B. \(\frac{17}{36}\)
• C. \(\frac{7}{12}\)
• D. \(\frac{1}{2}\)

Hint:

For card-selection probability questions, first count the multiplicity of each card value carefully. Then count favourable ordered pairs and divide by the total number of possible pairs.

Answer 1

The Correct Option is D