Question:medium

In a monohybrid cross between two heterozygous pea plants (Pp x Pp), what is the expected phenotypic ratio of the offspring?

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A monohybrid cross between two heterozygous individuals typically produces a 3:1 phenotypic ratio, where the dominant allele masks the expression of the recessive allele.
Updated On: Feb 19, 2026
  • 3:1
  • 1:2:1
  • 1:1
  • 4:0
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The Correct Option is A

Solution and Explanation

During a monohybrid cross of two heterozygous pea plants (Pp x Pp), allele segregation follows Mendelian inheritance. The offspring can have the following genotypes:
- PP (homozygous dominant)
- Pp (heterozygous)
- pp (homozygous recessive)
A Punnett square is employed to ascertain genotypic and phenotypic ratios.
- The genotypic ratio is:
- 1 PP : 2 Pp : 1 pp
As P (dominant) confers the dominant phenotype and p (recessive) confers the recessive phenotype, the phenotypic ratio is:
- 3 dominant (PP and Pp) : 1 recessive (pp)
Therefore, the predicted phenotypic ratio for the offspring is 3:1.
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