Question:medium

In a Mohr--Coulomb failure criterion, the ratio of the uniaxial compressive strength to the tensile strength is

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For the Mohr--Coulomb criterion, \[ \boxed{ \frac{\sigma_c}{\sigma_t} = \frac{1+\sin\phi}{1-\sin\phi} } \] where \(\phi\) is the angle of internal friction.
Updated On: Jul 14, 2026
  • \(\dfrac{1+\sin\phi}{1-\sin\phi}\)
  • \(\dfrac{1-\sin\phi}{1+\sin\phi}\)
  • \(C\left(\dfrac{1-\sin\phi}{1+\sin\phi}\right)\)
  • \(2C\left(\dfrac{1-\sin\phi}{1+\sin\phi}\right)\)
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The Correct Option is A

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