Question:easy

In a given mechanism, the number of links are five. Then the number of instantaneous centres of the mechanism is

Show Hint

This formula counts how many unique pairs you can make from $n$ items. For common mechanisms, the number of I-centers increases rapidly as links are added: - 4 links $\rightarrow$ 6 I-centers - 5 links $\rightarrow$ 10 I-centers - 6 links $\rightarrow$ 15 I-centers
Updated On: Jul 4, 2026
  • $10$
  • $6$
  • $5$
  • $15$
Show Solution

The Correct Option is A

Solution and Explanation

Every pair of links in a mechanism, whether they physically touch each other or not, has one instantaneous centre associated with it, because Kennedy's theorem treats every possible pair of links, including the fixed one, as sharing a common point of zero relative velocity at that instant. So the total count is simply the number of ways to pick 2 links out of the total, which for 5 links is \( \binom{5}{2} = \dfrac{5 \times 4}{2} = 10 \), matching option (A).
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