Question:medium
In a G.P., $1, \frac{1}{2}, \frac{1}{4}, \ldots$, when the first $n$ number of terms are added, the sum is $\frac{1023}{512}$. Then the value of $n$ is
In a G.P., $1, \frac{1}{2}, \frac{1}{4}, \ldots$, when the first $n$ number of terms are added, the sum is $\frac{1023}{512}$. Then the value of $n$ is
Show Hint
For G.P. sums, always simplify the denominator early. Converting the result into powers of 2 or 3 often makes solving much faster.
Updated On: Apr 30, 2026
- $10$
- $12$
- $14$
- $16$
- $18$
Show Solution
The Correct Option is A
Solution and Explanation
Was this answer helpful?
0
Top Questions on geometric progression
- The sum of two numbers is 6 times their geometric mean, show that numbers are in the ratio (3+2√2) : (3-2√2).
- CBSE Class XI
- Mathematics
- geometric progression
- Find the value of n so that \(\frac{a^{n+1}+b^{n+1}}{a^n+b^n }\)n may be the geometric mean between a and b.
- CBSE Class XI
- Mathematics
- geometric progression
- If a, b, c and d are in G.P. show that (a 2 + b 2 + c 2 ) (b 2 + c 2 + d 2 ) = (ab + bc + cd)2.
- CBSE Class XI
- Mathematics
- geometric progression
If the first and the nth term of a G.P. are a and b, respectively, and if P is the product of n terms, prove that P2 = (ab) n .
- CBSE Class XI
- Mathematics
- geometric progression
- Want to practice more? Try solving extra ecology questions todayView All Questions
