Question

In a forward biased semiconductor potential changes from 0.9V to 0.6 V. Find current if resistance is $1\Omega$

• A. 300 mA
• B. 200 mA
• C. 450 mA

Hint:

When dealing with active semiconductor devices operating in non-linear regions, always utilize the dynamic resistance ($\frac{\Delta V}{\Delta I}$) rather than the static resistance ($\frac{V}{I}$).

Answer 1

The Correct Option is A

To solve the given problem, we need to determine the current flowing through the semiconductor when its potential changes from 0.9 V to 0.6 V with a resistance of 1 Ω.

1. To find the current flowing through a resistor, we use Ohm's Law, which states: \(I = \frac{V}{R}\) where \(I\) is the current, \(V\) is the potential difference, and \(R\) is the resistance.
2. The given potential change is from 0.9 V to 0.6 V, meaning the potential difference \(\Delta V\) is: \(\Delta V = 0.9 \text{ V} - 0.6 \text{ V} = 0.3 \text{ V}\)
3. The resistance \(R\) is given as \(1 \, \Omega\).
4. Substitute the values in the Ohm's Law formula to calculate the current \(I\): \(I = \frac{0.3 \text{ V}}{1 \, \Omega} = 0.3 \, \text{A}\). Converting this into milliamperes (since 1 A = 1000 mA), we get \(I = 300 \, \text{mA}\).

Therefore, the current flowing through the semiconductor is 300 mA. The correct option is 300 mA.