Step 1: Let Usual Speed be x
Distance = 600 km
Usual time:
t₁ = 600 / x
Reduced speed = x − 200
New time:
t₂ = 600 / (x − 200)
Given:
t₂ − t₁ = 0.5 hours
Step 2: Form the Equation
600/(x − 200) − 600/x = 1/2
Take LCM:
600x − 600(x − 200) / x(x − 200) = 1/2
Simplify numerator:
600x − 600x + 120000
= 120000
So equation becomes:
120000 / x(x − 200) = 1/2
Step 3: Cross Multiply
240000 = x(x − 200)
x² − 200x − 240000 = 0
Factorise:
x² − 600x + 400x − 240000 = 0
(x − 600)(x + 400) = 0
x = 600 or x = −400
Speed cannot be negative,
x = 600 km/h
Step 4: Find Scheduled Duration
Scheduled time = 600 / 600
= 1 hour
Final Answer:
Scheduled duration of the flight = 1 hour