Question:medium
In a common emitter amplifier the input signal is applied across
In a common emitter amplifier the input signal is applied across
Show Hint
CE input = Base-Emitter; Output = Collector-Emitter.
Updated On: Apr 10, 2026
- anywhere
- emitter-collector
- collector-base
- base-emitter
Show Solution
The Correct Option is D
Solution and Explanation
Was this answer helpful?
0
Top Questions on Ionic Equilibrium In Solution
- CaCO$₃$(s) $\rightleftharpoons$ CaO(s) + CO$₂$(g), \( K_{p1} = 8 \times 10^{-2} \)
C(s) + CO$₂$(g) $\rightleftharpoons$ 2CO(g), \( K_{p2} = 2 \)
If the partial pressure of CO at equilibrium is \( x \times 10^{-1} \) atm, then find the value of \( x \).
- JEE Main - 2026
- Chemistry
- Ionic Equilibrium In Solution
- Calculate the equilibrium constant for the following equilibrium:
\[ \frac{1}{2} X_2 + \frac{1}{2} Y_2 \rightleftharpoons XYZ \] Given: \[ 2XY \rightleftharpoons X_2 + Y_2, \quad K_1 = 2.5 \times 10^{-5} \] \[ \frac{1}{2} Z_2 + XY \rightleftharpoons XYZ, \quad K_2 = 5 \times 10^{-3} \]- JEE Main - 2026
- Chemistry
- Ionic Equilibrium In Solution
- 0.1 mole of \( H_2S \) is added in 1 liter of 0.1 HCl solution. Calculate the concentration of \( HS^{-} \).
[Given \( K_{a1} = 8.3 \times 10^{-8} \) and \( K_{a2} = 10^{-13} \)]
- JEE Main - 2026
- Chemistry
- Ionic Equilibrium In Solution
- 20 ml of 0.2 M HA (\( K_a = 5 \times 10^{-4} \)) is titrated with 10 ml of 0.2 M NaOH solution. Calculate the initial and final value of pH of the solution. [Given \( \log 5 = 0.7 \)]
- JEE Main - 2026
- Chemistry
- Ionic Equilibrium In Solution
- Want to practice more? Try solving extra ecology questions todayView All Questions
