Question

In a certain code language, “PENCIL” is written as “QFODJM”. How will “MARKER” be written in that code?

• A. NBSLFS
• B. NBSJFS
• C. NCSLFS
• D. NARKFS

Hint:

To eliminate choices quickly, check the first two letters and the last letter: $\text{M}\rightarrow\text{N}$, $\text{A}\rightarrow\text{B}$, and $\text{R}\rightarrow\text{S}$. This tells you the code must start with "NB..." and end with "...S". This quickly narrows down your options and confirms choice (a)!

Answer 1

The Correct Option is A

Step 1: Understanding the Concept:
Coding-decoding puzzles based on alphabet shifts require finding a mapping rule. We look at the position of each letter in the word relative to its position in the coded counterpart.
The rule usually involves moving letters forward (+) or backward (-) by a fixed number of positions in the English alphabet (A-Z).
Step 2: Key Formula or Approach:
Identify the shift for the first few letters to determine the pattern. Standard patterns include +1, +2, or even alternating shifts like +1, -1.
Step 3: Detailed Explanation:
Let's analyze the reference pattern: PENCIL \( \rightarrow \) QFODJM
P \( \rightarrow \) Q (The letter immediately after P is Q, so +1 shift)
E \( \rightarrow \) F (The letter immediately after E is F, so +1 shift)
N \( \rightarrow \) O (The letter immediately after N is O, so +1 shift)
C \( \rightarrow \) D (The letter immediately after C is D, so +1 shift)
I \( \rightarrow \) J (The letter immediately after I is J, so +1 shift)
L \( \rightarrow \) M (The letter immediately after L is M, so +1 shift)
The encryption rule is: Every letter is replaced by the letter immediately following it (+1 shift).
Now, applying this identical +1 rule to the target word MARKER:
M \( \rightarrow \) N
A \( \rightarrow \) B
R \( \rightarrow \) S
K \( \rightarrow \) L
E \( \rightarrow \) F
R \( \rightarrow \) S
Concatenating these letters results in: NBSLFS.
Comparing this string with the options, option (A) is an exact match.
Step 4: Final Answer:
The word MARKER will be written as NBSLFS.