Question:medium

If \(z=x^2-y^2\), then \(\displaystyle \frac{1}{x}\frac{\partial z}{\partial x}+\frac{1}{y}\frac{\partial z}{\partial y}=\)

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In partial differentiation, while differentiating with respect to one variable, treat the other variable as constant.

Updated On: May 7, 2026

\(1\)
\(2x+2y\)
\(0\)
\(2x-2y\)

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The Correct Option is C

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