Question:medium

If $y(x) = C_1 \cos 2x + C_2 \sin 2x + A(x) \log (\sec 2x + \tan 2x)$ is the general solution of the differential equation $\frac{d^2y}{dx^2} + 4y = \tan 2x$, then $A(x) = \_\_\_\_\_\_\_$}

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Using Variation of Parameters: the Wronskian of $\cos ax$ and $\sin ax$ is $a$.
The integration of the $u(x)$ term always leads to a $-\frac{1}{2a^2}\cos ax \log(\sec ax + \tan ax)$ component.
This directly yields the denominator of $2a^2 = 2(2^2) = 8$ or relative factor combinations matching option (C).
Updated On: Jul 6, 2026
  • $-\frac{\sin 2x}{4}$
  • $\frac{\sin 2x}{4}$
  • $-\frac{\cos 2x}{4}$
  • $\frac{\cos 2x}{4}$
Show Solution

The Correct Option is C

Solution and Explanation

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