Question:medium

If \( (x, y) \) is equidistant from \( (a+b, b-a) \) and \( (a-b, a+b) \), then:

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The locus of points equidistant from two points is the perpendicular bisector of the segment joining them. The equation \( bx-ay=0 \) represents a straight line passing through the origin.
Updated On: May 1, 2026
  • \( x+y = 0 \)
  • \( bx-ay = 0 \)
  • \( ax-by = 0 \)
  • \( bx+ay = 0 \)
  • \( ax+by = 0 \)
Show Solution

The Correct Option is B

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