Question:medium

If $x = \tan^{-1} \left\{ \frac{\sqrt{1+t^2}-1}{t} \right\}, y = \cos^{-1} \left\{ \frac{1-t^2}{1+t^2} \right\}$, then $\frac{dy}{dx}$ is equal to

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Always look for trigonometric substitutions in inverse trig functions. For $1+t^2$, use $t = \tan \theta$.
Updated On: Apr 30, 2026
  • 2
  • $\frac{1}{2}$
  • 4
  • $\frac{1}{4}$
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The Correct Option is C

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