Question:medium

If $x = \sqrt{1-\tan y}$, then $\frac{dy}{dx} =$

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When asked to find $\frac{dy}{dx}$ from a relation where $x$ is given in terms of $y$, it's often easier to first algebraically solve for $y$ in terms of $x$ and then perform direct differentiation, rather than using implicit differentiation or finding $\frac{dx}{dy}$ first.

Updated On: Mar 30, 2026

$\frac{2x}{x^4+2x^2+2}$
$-\frac{2x}{x^4-2x^2+2}$
$\frac{2x}{x^4-2x^2+2}$
$-\frac{2x}{x^4+2x^2+2}$

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The Correct Option is B

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