Question:medium
If $x = \frac{3t}{1+t^3}$ and $y = \frac{3t^2}{1+t^3}$, then $\frac{dy}{dx}$ at $t=1$ equals
If $x = \frac{3t}{1+t^3}$ and $y = \frac{3t^2}{1+t^3}$, then $\frac{dy}{dx}$ at $t=1$ equals
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In parametric problems, always simplify before substituting values.
Updated On: Apr 30, 2026
- $-6$
- $-1$
- $1$
- $6$
- $4$
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The Correct Option is B
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