Question:medium

If \(x + \dfrac{1}{x} = 4\), then what is the value of \(x^2 + \dfrac{1}{x^2}\)?

Show Hint

Square the given expression; the cross term is 2.
Updated On: Jul 8, 2026
  • 18
  • 12
  • 16
  • 14
Show Solution

The Correct Option is D

Solution and Explanation

Use the identity $x^2 + \dfrac{1}{x^2} = \left(x + \dfrac{1}{x}\right)^2 - 2 = 4^2 - 2 = 16 - 2 = 14.$
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