Question:medium
If \( x \) and \( y \) are the roots of the equation \( x^2 + bx + 1 = 0 \), then the value of \( \frac{1}{x+b} + \frac{1}{y+b} \) is:
If \( x \) and \( y \) are the roots of the equation \( x^2 + bx + 1 = 0 \), then the value of \( \frac{1}{x+b} + \frac{1}{y+b} \) is:
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When the variable from the denominator appears in the original equation (like \( x+b \)), try to isolate that term in the quadratic equation first. It often turns a fraction into a simple polynomial.
Updated On: May 1, 2026
- \( \frac{1}{b} \)
- \( b \)
- \( \frac{1}{2b} \)
- \( 2b \)
- \( 1 \)
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The Correct Option is B
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