We are given the differential equation:
x⁴ dy + (4x³y + 2 sin x) dx = 0
First, rearrange the equation to express dy/dx:
x⁴ dy = −(4x³y + 2 sin x) dx
dy/dx = −(4x³y + 2 sin x) / x⁴
Simplifying:
dy/dx + (4/x) y = −(2 sin x) / x⁴
This is a first-order linear differential equation of the form:
dy/dx + P(x)y = Q(x)
where P(x) = 4/x.
Step 1: Find the integrating factor
IF = e∫(4/x) dx = e4 ln x = x⁴
Step 2: Multiply the equation by the integrating factor
x⁴ dy/dx + 4x³y = −2 sin x
The left side becomes the derivative of x⁴y:
d(x⁴y)/dx = −2 sin x
Step 3: Integrate both sides
x⁴y = ∫(−2 sin x) dx
x⁴y = 2 cos x + C
Step 4: Apply the initial condition
Given f(π/2) = 0, substitute x = π/2 and y = 0:
(π/2)⁴ · 0 = 2 cos(π/2) + C
0 = 0 + C
C = 0
Step 5: Write the final solution
x⁴y = 2 cos x
y = f(x) = 2 cos x / x⁴
Step 6: Evaluate π⁴ f(π/3)
f(π/3) = 2 cos(π/3) / (π/3)⁴
Since cos(π/3) = 1/2:
f(π/3) = 1 / (π/3)⁴
π⁴ f(π/3) = π⁴ / (π/3)⁴ = 3⁴
π⁴ f(π/3) = 81
Final Answer:
81