If \(x_0=1.2\) is the initial guess of the solution of \(x^3+2x-1=0\), then the \(1^{\text{st}}\) iteration solution \(x_1=\)
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Newton-Raphson iteration is
\[
\boxed{
x_{n+1}
=
x_n-\frac{f(x_n)}{f'(x_n)}.
}
\]
It provides quadratic convergence when the initial guess is sufficiently close to the root.