Question:easy

If \(\vec{r}=4\hat{i}+2\hat{j}+7\hat{k}+\lambda (3\hat{i}-5\hat{k})\) is the vector equation of the line passing through \((7,2,2)\), where \(\lambda\) is parameter, then the value of \(\lambda\) is...

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Equate the position vector of the given point with the line equation and compare components.
Updated On: Nov 12, 2026
  • \(-1\)
  • \(2\)
  • \(-2\)
  • \(1\)
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Parametric Form
The line is $x=4+3\lambda$, $y=2$, $z=7-5\lambda$.

Step 2: Substitute the Point
Put $x=7$ to get $3\lambda=3$, and $z=2$ to get $5\lambda=5$.

Step 3: Conclude
Both give $\lambda=1$, and $y=2$ already matches.

Final Answer:
The parameter value is 1. \[ \boxed{\text{(D) }1} \]
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