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If $|\vec{a}| = \sqrt{26}, \; |\vec{b}| = \sqrt{3}$ and $\vec{a} \times \vec{b} = 5\hat{i} + \hat{j} - 4\hat{k}$, then $\vec{a} \cdot \vec{b} =$:
If $|\vec{a}| = \sqrt{26}, \; |\vec{b}| = \sqrt{3}$ and $\vec{a} \times \vec{b} = 5\hat{i} + \hat{j} - 4\hat{k}$, then $\vec{a} \cdot \vec{b} =$:
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Use identity linking dot and cross product to avoid finding vectors explicitly.
Updated On: Apr 24, 2026
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