If \( \vec{a} \cdot \vec{b} = 0 \) and \( \vec{a} + \vec{b} \) makes an angle of \( 60^\circ \) with \( \vec{a} \), then:
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Think of this geometrically as a right-angled triangle where the sides are magnitudes \( |\vec{a}| \) and \( |\vec{b}| \). Then \( \tan(\text{angle with } a) = \text{Opposite}/\text{Adjacent} = |\vec{b}|/|\vec{a}| \).