To solve the problem of finding the sum of the greatest and the smallest values of \(|\lambda \vec{a}|\), we need to first understand how scalar multiplication affects the magnitude of a vector. Given that \(|\vec{a}| = 5\) and \(-2 \leq \lambda \leq 1\), we must examine the expression \(|\lambda \vec{a}| = |\lambda| |\vec{a}|\).
- Calculate \(|\lambda| |\vec{a}|\):
- The magnitude of a vector scaled by a scalar \(\lambda\) is the absolute value of the scalar times the magnitude of the vector.
- Thus, \(|\lambda \vec{a}| = |\lambda| \cdot 5\).
- Determine the range of \(|\lambda|:\)
- The given range for \(\lambda\) is \(-2 \leq \lambda \leq 1\).
- Therefore, the range for \(|\lambda|\) would be \(0 \leq |\lambda| \leq 2\) (since the absolute value of a number is always non-negative and maximum covers both ends).
- Find the smallest and greatest values of \(|\lambda| |\vec{a}|:\)
- Smallest value: When \(|\lambda| = 0\), \(|\lambda \vec{a}| = 0 \times 5 = 0\).
- Greatest value: When \(|\lambda| = 2\), \(|\lambda \vec{a}| = 2 \times 5 = 10\).
- Calculate the sum of the smallest and greatest values:
Therefore, the sum of the greatest and the smallest value of \(|\lambda \vec{a}|\) is \(10\). The correct answer is 10.