Question:medium

If $\vec{a} = 2\vec{i} + 3\vec{j} - \vec{k}$, $\vec{b} = -\vec{i} + 2\vec{j} - 4\vec{k}$ and $\vec{c} = \vec{i} + \vec{j} + \vec{k}$, then $(\vec{a} \times \vec{b}) \cdot (\vec{a} \times \vec{c}) =$

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Using Lagrange's identity for cross products saves significant time compared to computing the cross products $\vec{a}\times\vec{b}$ and $\vec{a}\times\vec{c}$ individually.
Updated On: May 31, 2026
  • $-74$
  • $74$
  • $-42$
  • $42$
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The Correct Option is A

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